5x^(2/3)-29x^(1/3)-6=0

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Solution for 5x^(2/3)-29x^(1/3)-6=0 equation: 


x in (-oo:+oo)

5*x^(2/3)-(29*x^(1/3))-6 = 0

5*x^(2/3)-29*x^(1/3)-6 = 0

t_1 = x^(1/3)

5*t_1^2-29*t_1^1-6 = 0

5*t_1^2-29*t_1-6 = 0

DELTA = (-29)^2-(-6*4*5)

DELTA = 961

DELTA > 0

t_1 = (961^(1/2)+29)/(2*5) or t_1 = (29-961^(1/2))/(2*5)

t_1 = 6 or t_1 = -1/5

t_1 = -1/5

x^(1/3)+1/5 = 0

1*x^(1/3) = -1/5 // : 1

x^(1/3) = -1/5

( -1/5 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 6

x^(1/3)-6 = 0

1*x^(1/3) = 6 // : 1

x^(1/3) = 6

x^(1/3) = 6 // ^ 3

x = 216

x = 216

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